[wp-hackers] DOING_AJAX all the time

[Dion Hulse (dd32)]

Enable PHP Warnings/Notices and you'll get an error along the lines of
"Constant DOING_AJAX undefined, Assuming 'DOING_AJAX'" (a string).
so what your code is really saying is... If the string "DOING_AJAX" is
not empty, echo yes.

This is because the DOING_AJAX define is only defined when it's true,
so you should be doing:
if ( defined('DOING_AJAX') && DOING_AJAX )

As a easier way to catch this, always use something such as var_dump()
and inspect the type of the variable printed is what you expect (ie. a
boolean, and not a string of DOING_AJAX).

D

On 30 January 2012 15:09, Tom Barrett <tcbarrett at gmail.com> wrote:
> What happens if you do this:
>
> <?php echo 'DOING_AJAX: ' . ( (defined('DOING_AJAX') && DOING_AJAX) ? 'yes'
> : 'no' ); exit; ?>
>
> On 30 January 2012 14:57, Steve Taylor <steve at sltaylor.co.uk> wrote:
>
>> I have a site in development that seems to think it's DOING_AJAX all
>> the time. There are AJAX aspects to the front-end, but even non-AJAX
>> requests seem to have this flag set.
>>
>> So, if I put this line in header.php, functions.php, a plugin:
>>
>> <?php echo 'DOING_AJAX: ' . ( DOING_AJAX ? 'yes' : 'no' ); exit; ?>
>>
>> Even if I just make a plain request to a page in the browser, I get:
>>
>> DOING_AJAX: yes
>>
>> I'm rushed so I'm heading for a workaround for now - just wondered if
>> anyone had any ideas?
>>
>> Needless to say I've double-checked for the constant being defined,
>> and it's only in admin-ajax.php. Any idea how this may be being
>> included on a normal request?
>>
>> Thanks,
>>
>> Steve Taylor
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>> wp-hackers at lists.automattic.com
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>>
>
>
>
> --
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